Article

e - Exponent Constant

Wednesday, 3 December 2025

Warning

This document was partially AI generated, however adapted.

ee is used as a base because it has the unique property where the gradient of y=exy = e^x is equal to exe^x itself.

Key Definitions

  • Definition: ln(x)\ln(x) is simply shorthand for loge(x)\log_{e}(x).
  • Inverse Property: exe^x and ln(x)\ln(x) are inverse functions. They “undo” each other.
    • eln(x)=xe^{\ln(x)} = x
    • ln(ex)=x\ln(e^x) = x

Log Laws for ln(x)\ln(x)

  1. ln(a)+ln(b)=ln(ab)\ln(a) + \ln(b) = \ln(ab)
  2. ln(a)ln(b)=ln(ab)\ln(a) - \ln(b) = \ln\left(\frac{a}{b}\right)
  3. ln(ak)=kln(a)\ln(a^k) = k \ln(a)
  4. Crucial Values: ln(e)=1\ln(e) = 1 and ln(1)=0\ln(1) = 0.

Solving Equations with ee and ln\ln

Example 1: Removing ee

e2x+3=7e^{2x+3} = 7

Take ln\ln of both sides:

ln(e2x+3)=ln(7)\ln(e^{2x+3}) = \ln(7)

2x+3=ln(7)2x + 3 = \ln(7)

x=ln(7)32x = \frac{\ln(7) - 3}{2}

Example 2: Removing ln\ln

ln(x5)=2\ln(x - 5) = 2

Apply ee to both sides (exponentiate):

eln(x5)=e2e^{\ln(x-5)} = e^2

x5=e2x - 5 = e^2

x=e2+5x = e^2 + 5 **